Construct a triangle congruent to ∆ABC with one side of the triangle lying on line DE. 
Hint:  start by finding a point F  on DE so that DF = AB.

A = (-2.7, 3.5)
B = (1.02, 2.8)
C = (-0.94, 4.88)
D = (3, 1.22)
E = (14.34, 0.22)
a = Line(D, E)
poly1, c, a_1, b = Polygon(A, B, C)